مبرهنة طاليس في الهندسة تقول أنه إذا قطع مستقيمان 3 مستقيمات متوازية فإننا نحصل على:
- 1 الصياغة
- 2 التطبيقات
- 3 Proof
- 4 طالع أيضاً
- 5 وصلات خارجية
- 6 المصادر
S is the point the intersection of 2 lines and A,B are the intersections of the first line with the 2 parallels, such that B is further away from S than A, and similarly are C, D the intersections of the second line with the 2 parallels such that D is further away from S than C.
- The ratios of the any 2 segments on the first line equals the rations of the according segments on the second line: , ,
- The ratio of the 2 segments on the same line starting at S equals the ratio of the segments on the parallels:
- The converse of the first statement is true as well, i.e. if the 2 intersecting lines are intercepted by 2 arbitrary lines and holds then the 2 intercepting lines are parallel. However the converse of the second statement is not true.
- If you have more than 2 lines intersecting in S, then ratio of the 2 segments on a parallel equals the ratio of the according segments on the other parallel. An example for the case of 3 lines is given the second graphic below.
الصياغة الجبرية لمنشآت الفرجار والمسطرة
There are 3 famous problems in elementary geometry, which were posed by the Greek in terms of Compass and straightedge constructions.
Their solution took more than 2000 years until all 3 of them finally were settled in the 19th century using algebraic methods that had become available during that period of time. In order to reformulate them in algebraic terms using field extensions, one needs to match field operations with compass and straightedge constructions. In particular it is important to assure that for 2 given line segments, a new line segment can be constructed such that its length equals the product of lengths of the other 2. Similarly one needs to be able to construct, for a line segment of length , a new line segment of length . The intercept theorem can be used to show that in both cases the construction is possible.
تقسيم خط مستقيم بنسبة معينة
To divide an arbitrary line segment in a ratio you draw an arbitrary angle in A with as one leg. One other leg you construct equidistant points, then you draw line through the last point and B and parallel line through the mth point. This parallel line divides in the desired ratio. The graphic to the right shows the partition of a line sgement in a ratio.
Height of the Cheops Pyramid
According to some historical sources the Greek mathematician Thales applied the intercept theorem to determine the height
of the cheops pyramid. He measured the shadow of a pole (B) with 2m, its height (A) with 1.63m, the shadow of the cheops pyramid with 63m, its base length with 230m. From that he computed
قياس عرض النهر
The intercept theorem can be used determine a distance that cannot be measured directly, such as the width of a river or a lake, tall buildings or similar. The graphic to right illustrates the measuring of the width of a river. The segments ,, are measured and used to compute the wanted distance .
Parallel Lines in Triangles and Trapezoids
The intercept theorem can be used to prove that a certain construction yields a parallel line (segment).
If the midpoints of 2 triangle sides are connected then the resulting line segment is parallel to the 3rd triangle side.
If the midpoints of 2 the non parallel sides of a trapezoid are connected, then the result line segment is parallel to the other 2 sides of the trapezoid.
Due to heights of equal length ( ) we have and therefore . This yields
Plugging in the actual formula for triangle areas () transforms that into
Cancelling the common factors results in:
Now use (b) to replace and in (a):
Draw an additional parallel to through A. This parallel intersects in G. Then you have and due to claim 1
Assume and are not parallel. Then the parallel line to through intersects in . Since is true, we have
Can be shown by applying the intercept theorem for 2 lines.